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Three players A, B, & C take turns rolling a pair of dice. The winner is the first player who obtains the sum of 7 (P[7] = 1/6) on a given roll of the dice. If A rolls 1st, then B, then C, then back to A (etc. etc. etc.). What is the P[A wins], P[B wins], P[C wins]? P[A] = 1/3, P[B] = 1/3, P[C] = 1/3 P[A] = 14/36, P[B] = 13/36, P[C] = 12/36 P[A] = 4/7, P[B] = 2/7, P[C] = 1/7 P[A] = 233/648, P[B] = 215/648, P[C] = 200/648 P[A] = 36/91, P[B] = 30/91, P[C] = 25/91

You may use the calculator above and this area as scratch paper. To see the solution just click on the button.

Carlos Rodriguez <carlos@math.albany.edu>

This problem was contributed by a student. It is offered as it is with no warranty of any kind
Last modified: Wed May 13 12:29:11 EDT 1998