:8. Solution.  First we find the z-score corresponding to the
80th percentile.  20% of the area under the normal curve is to
the right of z.  By symmetry, 20% is to the left of -z.  So 60%
is between -z and z.  Looking at the normal table, we see that
z=.85 corresponds to A(z)=60.47%, so the z we are looking for is
about equal to .85. This corresponds to an LSAT score of 650 +
.85x60 = 650 + 51 = 701, which is closest to 700.