:10a.  Solution.  Since (76-66)/5 = 2, the members who are 76
inches tall are 2 standard deviations above average. Since
-0.90 x 2 = -1.8,  their average weight is 1.8 SD's below the
average weight of the sample, which is 140 - (1.8 x 40) = 140 -
72 = 68 lbs.